(x² + y² + 1)dx + x(x – 2y)dy = 0.
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Step 1
First, we can rewrite the given equation as: (x^2 + y^2 + 1)dx + x(xy - 2y)dy = 0 Now, we can rearrange the terms to make it look like an exact differential equation: (x^2 + y^2 + 1)dx + (x^2y - 2xy)dy = 0 To check if this equation is exact, we need to find the Show more…
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