00:01
In problem 7, given series vary from 1 to infinity, negative 1 to the power n, x to the power of n over n times of 5 to the power of n.
00:17
So first we need to find the center.
00:22
So this can be written as summation vary from 1 to infinity, negative 1 to the power n, that is x negative 0 to the whole power n over n times of 5 to the power of n.
00:34
So that is center, that is x naught is equal to 0.
00:37
To find radius of convergence r by ratio test, we have the limit n to the power of a n plus 1 over a n is equal to the limit n to the power of negative 1 to the power n plus 1 multiplied to x to the power n plus 1 over n plus 1 multiplied to 5 to the power n plus 1 multiplied to n multiplied to 5 to the power of n over negative 1 to the power n multiplied to x to the power of n.
01:24
So this value is equal to the limit n to the power of that is negative 1 multiplied to x over 1 plus 1 over n, that is 5.
01:40
This limit will be mod of x over 5.
01:47
So series will converge if the limit will be less than 1...