00:01
The given function f of x, y is equal to 4 times of the square root of x, y over 12.
00:12
So, to find linear approximation at a point 8, 6, 8 and also approximate the value of the function f of 8, 1, 7, 6, 2, 3 up to 3 decimal places.
00:45
The given function f can be written as that is a 4 over square root of 12, x to the power of 1 over 2, y to the power of 1 over 2 and that is 2 over root 3, x to the power of 1 over 2, y to the power of 1 over 2.
01:03
Differentiate a with respect to x partially, then we have 2 over root 3 multiplied to 1 over 2, x to the power of negative 1 over 2, y to the power of 1 over 2 that is 1 over root 3, the square root of y over x and value of derivative with respect to x at 8, 6 is equal to 1 over root 3, square root of 6 over 8 and that is 1 over 2...