Question

y = -x^3 + 3, x ≤ 0 -x^2 + 4x, x > 0 Find the critical numbers. (Hint: Check for discontinuities.) (Enter your answers as a comma-separated list. If an answer does not exist, enter DNE.) x = Find the open intervals on which the function is increasing or decreasing. (Enter your answers using interval notation. If an answer does not exist, enter DNE.) increasing decreasing

Name: y x3 3 x 0 x2 4x x 0 find the critical numbers hint check for discontinuities enter your answers as a comma separated list if an answer does not exist enter dne x find the open intervals on 89556
Uploaded: 2022-06-22T10:31:56-08:00
Duration: 2 min 53 s
Channel: Vincenzo Zaccaro
Description: y x3 3 x 0 x2 4x x 0 find the critical numbers hint check for discontinuities enter your answers as a comma separated list if an answer does not exist enter dne x find the open intervals on 89556

          y = 
-x^3 + 3,    
x ≤ 0
-x^2 + 4x,    
x > 0
Find the critical numbers. (Hint: Check for discontinuities.) (Enter your answers as a comma-separated list. If an answer does not exist, enter DNE.)
x =
Find the open intervals on which the function is increasing or decreasing. (Enter your answers using interval notation. If an answer does not exist, enter DNE.)
increasing
decreasing

Added by Jose Ramon C.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Vincenzo Zaccaro

06/22/2022

Step 1

Step 1:** The critical number is found by setting the derivative equal to 0 and solving for x: \[ -3x^2 = 0 \] \[ x = 0 \] ** Show more…

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y = -x^3 + 3, x ≤ 0 -x^2 + 4x, x > 0 Find the critical numbers. (Hint: Check for discontinuities.) (Enter your answers as a comma-separated list. If an answer does not exist, enter DNE.) x = Find the open intervals on which the function is increasing or decreasing. (Enter your answers using interval notation. If an answer does not exist, enter DNE.) increasing decreasing