00:01
Hi, today we are solving the question in which we have to assume that we can run at a speed of 8 meter per second.
00:09
So speed is 8 meters per second and swim at a rate of 2 meters per second.
00:23
So swim rate is equal to 2 meter per second.
00:34
So now let us say that we run x meter along the shore before diving into the water and then swim on a straight line out to the swimmer.
00:57
So it is given that you can run at a speed of 8 meter per second and swim at a rate of 2 meter per second.
01:05
And we know that if rate is constant, so distance is equal to rate into 10.
01:18
Time or time is equal to distance upon rate so the time it takes you to reach the swimmer will be t x is equal to distance of running by speed of running plus distance of swimming by rate of swimming so on substituting the value here we get t xx is equal to x by 8 plus we don't know the distance so here swimming by now where distance of swimming can be obtained by under root 60 minus x square by the distance formula plus 40 whole square so distance of swimming is equal to under root 3 ,600 minus 120x plus x squared plus 1 ,600.
02:55
So similarly on solving it further, we get distance of swimming is equal to under root x square minus 120x plus 5200.
03:16
Now the total amount of time it takes to get to the swimmer if you run x meter round down the beaches t x is equal to x by 8 plus under root x square minus 120x plus 5200 by so similarly t x is equal to x by 8 plus x square minus 120x plus 5200 whole raise to the power 1 by 2 by 2...