You are given that $f(x)$ and $g(x)$ are differentiable functions and that $f(3) = 4$, $f'(3) = 7$, $g(3) = -2$, and $g'(3) = -7$. Find the value of $h'(3)$.\\ $h(x) = \frac{g(x)}{f(x)}$ Answer 2 Points $h'(3) = $
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