00:01
So for question a, let's call it the formula of the compound is cx, h, y, o, z, and t.
00:12
So by mass, so x minus 12 equal to 0 .4009 of the total mass of, let's call it m.
00:27
And we have y multiplied to 1, mass of m, h is 1, equal to 0 .0691 of m.
00:46
And we have y multiplied to, sorry, o, z, so z multiplied to 16 equal to 0 .3284 m.
01:00
And, so for question a, let's call it the formula of the compound is cx, h, y, and t multiplied 14 equal to 0 .1916 m.
01:20
So we have the relation x over y will be equal to 0 .4009, this is 12x, divided by 0 .0691 equal to, so for question a, let's call it the formula of cx, h, y, 5 .8.
01:59
So approximately is 1 .2, 1 over 2.
02:11
So for y over 16z equal 0 .0691 over 0 .4, we can just let do this.
02:35
So we have 12x over 16z equal to 0 .4009 over 0 .384, so it's equal to, so for question a, let's call it the formula cx, h, y, 1 .2.
03:00
So x over z approximately will be, so for question a, let's call it the formula of the compound is cx, h, y, 1 .63.
03:23
So we have x, 12x over 14t equal to 0 .4009 over 0 .1916 equal to, so for question a, let's call it the formula of the compound is cx, h, y, 2 .09.
03:49
So x over t approximately will be, so for question a, let's call it the formula of the compound is cx, h, y, 2 .44.
04:08
So the smallest x, y, z, t will be, so for question a, let's call it the formula of the compound is cx, h, y.
04:28
So for question a, let's call it the formula of the compound is cx, h, y.
04:37
So the molecule is c15h30o10nn3.
04:47
So if one more is contained.
04:58
So for question a, let's call it the formula of the compound is cx, h, y.
05:07
So the question b is the number of oxygen atom is in the compound is will be equal to the number of the total oxygen atom divided by avogadro number.
05:27
So it's equal to three.
05:34
So it means that we have the compound is c.
05:45
So for question a, let's call it the formula of the compound is cx, h, y, c10h20o3...