00:01
Hi, i'm david and i'm to help you answer your question.
00:03
Now let me bring up your question here.
00:06
In the question here we have the optimization problem.
00:09
So let me draw the box that will have open top.
00:13
So there will be the box here.
00:22
That base, it will be the square.
00:26
So it means that we will have this one will be the x, this one also the x, and then the height will be the y.
00:33
And there's no top here, so open, this one will be open here.
00:38
And now we are given the volume, it will equal to the 184.
00:45
And now because the volume of the box, we know that it will equal to the area on the base, it will be the x squared times the height, it will be the y.
00:54
And that will be the first equation we can link the volume to the variable x and y.
01:00
And on in the hand, we need to find the dimension that the box will should be to minimize the surface area.
01:06
On the hand, we know that the surface area s, it will equal to the area of the base will be the x square, and then we will plus the area of the four side, because they own the same, because of the base here will be the same...