00:02
Hi there.
00:03
In this question, we have a dilution problem, where we are taking some of the stock solution and adding more solvent to it to reduce the concentration.
00:14
So in a dilution problem, the concentration of the stock solution times its volume.
00:21
So we're going to use the ones to represent the stock solution.
00:24
So the concentration times the volume is going to be equal to the concentration of the diluted solution multiplied by its volume.
00:32
So we can use this equation to solve for the new concentration.
00:38
The concentration of our original stock solution is 50 .0 grams per liter.
00:48
And the volume of that that we're using is 125 milliliters.
00:55
We do not need to convert that volume to liters, and you'll see why in a moment.
01:00
All right, we're looking for the new concentration.
01:04
When we dilute this with additional solvent up to 1 ,000 milliliters, all right, so we want to solve for that new concentration...