Question

You have a 5.0 ml sample of a protein in 0.5M NaCl. You place the protein/salt sample inside dialysis tubing and place the bag in a large beaker of distilled water. Your goal is to remove as much NaCl from the sample as possible. Since you know that the final salt concentration will be the same inside the tubing as out, you can calculate the final concentration of the salt. Part 1 If you decide to place the dialysis bag in 4.0 L of distilled water for 12 h the final concentration of the salt would be .62 mM. Part 2 What would the final salt concentration be if instead of placing the dialysis bag in 4.0 L of distilled water for 12 h, you placed the bag in 1.0 L of distilled water for 6.0 h and then in another 1.0 L of fresh distilled water for another 6.0 h? It would be mM.

          You have a 5.0 ml sample of a protein in 0.5M NaCl. You place the protein/salt sample inside dialysis tubing and place the bag in a large beaker of distilled water. Your goal is to remove as much NaCl from the sample as possible. Since you know that the final salt concentration will be the same inside the tubing as out, you can calculate the final concentration of the salt.

Part 1

If you decide to place the dialysis bag in 4.0 L of distilled water for 12 h the final concentration of the salt would be
.62 mM.

Part 2

What would the final salt concentration be if instead of placing the dialysis bag in 4.0 L of distilled water for 12 h, you placed the bag in 1.0 L of distilled water for 6.0 h and then in another 1.0 L of fresh distilled water for another 6.0 h? It would be
mM.
        
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You have a 5.0 ml sample of a protein in 0.5M NaCl. You place the protein/salt sample inside dialysis tubing and place the bag in a large beaker of distilled water. Your goal is to remove as much NaCl from the sample as possible. Since you know that the final salt concentration will be the same inside the tubing as out, you can calculate the final concentration of the salt.

Part 1

If you decide to place the dialysis bag in 4.0 L of distilled water for 12 h the final concentration of the salt would be
.62 mM.

Part 2

What would the final salt concentration be if instead of placing the dialysis bag in 4.0 L of distilled water for 12 h, you placed the bag in 1.0 L of distilled water for 6.0 h and then in another 1.0 L of fresh distilled water for another 6.0 h? It would be
mM.

Added by Brenda M.

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Chemistry: Structure and Properties
Chemistry: Structure and Properties
Nivaldo Tro 2nd Edition
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You have a 5.0 ml sample of a protein in 0.5M NaCl. You place the protein/salt sample inside dialysis tubing and place the bag in a large beaker of distilled water. Your goal is to remove as much NaCl from the sample as possible. Since you know that the final salt concentration will be the same inside the tubing as out, you can calculate the final concentration of the salt. Part 1 If you decide to place the dialysis bag in 4.0 L of distilled water for 12 h the final concentration of the salt would be .62 mM. Part 2 What would the final salt concentration be if instead of placing the dialysis bag in 4.0 L of distilled water for 12 h, you placed the bag in 1.0 L of distilled water for 6.0 h and then in another 1.0 L of fresh distilled water for another 6.0 h? It would be mM.
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You have a 5.0 ml sample of a protein in 0.5M NaCl. You place the protein/salt sample inside dialysis tubing and place the bag in a large beaker of distilled water. Your goal is to remove as much NaCl from the sample as possible. Since you know that the final salt concentration will be the same inside the tubing as out, you can calculate the final concentration of the salt. Part 1 If you decide to place the dialysis bag in 4.0 L of distilled water for 12 h the final concentration of the salt would be .62 mM. Part 2 What would the final salt concentration be if instead of placing the dialysis bag in 4.0 L of distilled water for 12 h, you placed the bag in 1.0 L of distilled water for 6.0 h and then in another 1.0 L of fresh distilled water for another 6.0 h? It would be mM.

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You have a $5 \mathrm{mL}$ sample of a protein in $0.5 \mathrm{M}$ NaCl. You place the protein/salt sample inside dialysis tubing (see Fig. $2-14$ ) and place the bag in a large beaker of distilled water. If your goal is to remove as much $\mathrm{NaCl}$ from the sample as possible, which would be more effective: (1) placing the dialysis bag in 4 L of distilled water for $12 \mathrm{h},$ or (2) placing the bag in 1 L of distilled water for $6 \mathrm{h}$ and then in another 1 L of fresh distilled water for another $6 \mathrm{h} ?$

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You have a $5 \mathrm{mL}$ sample of a protein in $0.5 \mathrm{M}$ NaCl. You place the protein/salt sample inside dialysis tubing (see Fig. $2-14$ ) and place the bag in a large beaker of distilled water. If your goal is to remove as much $\mathrm{NaCl}$ from the sample as possible, which would be more effective: (1) placing the dialysis bag in 4 L of distilled water for $12 \mathrm{h},$ or (2) placing the bag in 1 L of distilled water for $6 \mathrm{h}$ and then in another 1 L of fresh distilled water for another $6 \mathrm{h} ?$

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Transcript

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00:01 So let's do this chemistry problem.
00:02 But before i get started, i recommend we do the question yourself and come back to see if you've got it right on that.
00:09 So hopefully you've done the question on and now let's work together.
00:12 So we're given a sample of protein and it is in 0 .5 minority off any cils salt.
00:17 We place the sample into a dialysis tubin and we place the bagna large bigger of water.
00:24 So what we want to do is remove as much as the salt possible.
00:29 We know that the final salt concentration would be the same inside the tubing us out.
00:34 You can calculate the final concentration of the salt, but if we decide to put the dialysis bag in 4 liters of distil water for 12 hours, we want to find out their final concentration of water, right? so what we would have to do for this is figure out the number of molds in nacl.
00:54 So we're given a sample of protein and zero point five.
01:02 We know that the formula is concentration equal to n we can find n subject so we have to do it we're already given the concentration of of the salt which is nrcl and we just have to multiply it by the volume that we're given so nacl, it would be 0 .5, 0 .05, it is getting a question, and i should guess about 0 .0 to 5 moles off.
02:04 And then we can figure out the mass of nacl from that, using this equation, m0's mass divided by mr we can make the mass m -tenth mr...
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