00:01
For this part, for our step one, for the calculation for the alicote 1, the concentration of protein in alicode is calculated using c1, v1 is equals to c2, v2 as follows.
00:14
C1 is the concentration, v1 is the volume of initial solution 1, c2 is the concentration, and v2 is the volume of final solution 2.
00:24
Putting the values in the above equation, so basically we will have 10 milligrams per ml times 5 micrometers is equals to c2 times 100 micrometers, or c2 is equals to 10 milligrams per ml times 5 microliters divided by 100 microlitors.
00:54
We have 0 .5 milligrams per ml.
00:58
So hence in alicote 1 we have 0 .5 milligrams per ml.
01:03
For our step two we need to calculate the milligrams of protein by this part we need to multiply the final protein by the final volume of alicote so which is 0 .2 milligrams per ml times 1 .0 ml so we will have 0 .5 milligrams.
01:23
Since the final volume is 1 .0 ml is all cases, the amount of milligrams of respective alicotes is equal to the concentration value, and the calculation for rest alicotes are done in egg cell...