You have a stock solution that contains 54 mg/mL of protein. You want to make a set of standards with the following concentrations: 6 mg/mL 0.67 mg/mL 0.075 mg/mL You need a minimum of 900 μL of each standard. Using the technique of serial dilution, explain how you would make your standards by filling in the chart below. Standard 1 Standard 2 Standard 3 Concentration 6 mg/mL 0.67 mg/mL 0.075 mg/mL Dilution factor From mL of concentrate mL of diluent Final dilution of stock Final volume/tube You have a stock solution that contains 40 mg/mL of protein. You want to make a set of standards with the following concentrations: 20 mg/mL 2.5 mg/mL 10 mg/mL 1.25 mg/mL 5 mg/mL 0.625 mg/mL You need a minimum of 600 μL of each standard. Using the technique of serial dilution, explain how you would make your standards by filling in the chart below. Std 1 Std 2 Std 3 Std 4 Std 5 Std 6 Concentration Dilution factor From mL of concentrate mL of diluent Final dilution of stock Final volume/tube Dilute the following, making sure you end up with a minimum volume of at least 5 mL. Stock conc Desired conc Dilution factor Volume stock Volume diluent 20 mg/mL 5 mg/mL 60 mg/mL 2 mg/mL 25 mg/mL 0.5 mg/mL 100 mg/mL 25 mg/mL 5 mg/mL 0.1 mg/mL 3 mg/mL 1.5 mg/mL 40% (v/v) 0.5% (v/v) 10x 1x 5x 1x 25% (w/v) 5% (w/v) 10^8 cells/mL 10^6 cells/mL 200 ppm 15 ppm 30% (w/v) 20% (w/v) 150% (v/v) 75% (v/v)
Added by Erin M.
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67 mg/mL): \[ \text{Dilution factor} = \frac{54 \text{ mg/mL}}{0.67 \text{ mg/mL}} \approx 80.60 \] For Standard 3 (0.075 mg/mL): \[ \text{Dilution factor} = \frac{54 \text{ mg/mL}}{0.075 \text{ mg/mL}} = 720 \] ** Show more…
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