You have intercepted a message encrytped with an affine cipher. The ciphertext starts with BBDJ and you know the plaintext starts with OOPS. The alpine text uses the alpha substitution y = (ax + b)mod 26. Find a and b.
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We'll use the standard A=0, B=1, C=2, etc. conversion. So, OOPS becomes 14 14 15 18 and BBDJ becomes 1 1 3 9. The affine cipher formula is y = (ax + b) mod 26. We have two pairs of x and y values from the plaintext and ciphertext: (14, 1) and (15, 3). We can Show more…
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