Question

You only have one attempt for this problem! Evaluate the following integrals: $\int e^{2x} dx = \frac{1}{2}e^{2x} + C$ $\int cos(x/5) dx = \boxed{} + C$ $\int sin(2x) dx = \boxed{} + C$ $\int \frac{1}{7x} dx = \boxed{} + C$

          You only have one attempt for this problem!
Evaluate the following integrals:
$\int e^{2x} dx = \frac{1}{2}e^{2x} + C$
$\int cos(x/5) dx = \boxed{} + C$
$\int sin(2x) dx = \boxed{} + C$
$\int \frac{1}{7x} dx = \boxed{} + C$

You only have one attempt for this problem!
Evaluate the following integrals:
∫ e^2x dx = (1)/(2)e^2x + C
∫ cos(x/5) dx = + C
∫ sin(2x) dx = + C
∫(1)/(7x) dx = + C

Added by Alexander S.

Calculus: Early Transcendentals

James Stewart 8th Edition

Thanks for your feedback!

You only have one attempt for this problem! Evaluate the following integrals: ∫ e^(2x) dx = ∫ cos(x/5) dx = ∫ sin(2x) dx = ∫ 1/(7x) dx = You only have one attempt for this problem! Evaluate the following integrals: ∫ e^(2x) dx = 2e^(2x) + C ∫ cos(x/5) dx = cos(x/5) + C ∫ sin(2x) dx = -1/2 cos(2x) + C ∫ 1/(7x) dx = (1/7) ln|x| + C