00:01
Hi, in this question we have given mass of kh is 0 .4410 gram.
00:06
We have given volume of nah initially 17 .55 milliliter and final volume is 37 .16 milliliter.
00:14
We need to find out the concentration of naoh.
00:17
So, volume of naoh will be vf minus vi equal to 19 .61 milliliter or 19 .6.
00:31
1 by 1 ,000 liter dilution law says that moles of khp will be equal to moles of n aohh moles of moles of kh will be mass of khp that is 0 .4410 gram by the molar mass of khp that is 204 .2 gram per mole we will get the value equal to 2 .15 into 10 to the per minus 3 mole.
01:14
So concentration of n .oh will be, and this is also moles of naoh.
01:25
Now, naoh concentration will be 2 .15 into 10 to the per minus 3 mole by 19 .61 by 1 ,000 liter, equal to 0 .109 mole per liter that is molar.
01:45
Next we have given concentration of nah is this.
01:49
Khp mass that is mass of kh that is small nkhp value is 0 .484 gram...