Your initial post is due by Thursday, July 31st, 11:59pm ET.
For full credit, your post must include the following items:
The notation $y'(t) = \frac{dy}{dt} = \frac{d}{dt}y$ was devised to suggest that the derivative of a function $y$ is the result of operating on the function $y$ with the differentiation operator $\frac{d}{dt}$. Indeed, second derivatives are formed by iterating the operation: $y''(t) = \frac{d^2y}{dt^2} = \frac{d}{dt}\frac{d}{dt}y$. Commonly, the symbol D is used instead of $\frac{d}{dt}$, and the second-order differential equation $y'' + 4y' + 3 = 0$ is represented by
$D^2y + 4Dy + 3y = (D^2 + 4D + 3)[y] = 0$.
Question: is $(D + 8t)D$ the same as $D(D + 8t)$? Please show your work to support your conclusion.
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