Your Learning Points 9 Carriere, Sophia Marae An 41.0 g sample of Mb at 390.0°C is placed in thermal contact with a 32. 8 g piece of Zn initially at 363.0°C. Calculate the final temperature after thermal equilibrium is achieved. The specific heats are $C_s(Mb(s)) = 0.25 J/g°C$ and $C_s(Zn(s)) = 0.39 J/g°C$ (A) 371. 7°C (B) 375.0°C (C) 380. 4°C (D) 372. 3°C (E) 379. 3°C
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The heat lost by the Mb can be calculated using the formula: Q_lost = m * C_s(Mb) * (T_final - T_initial) Q_lost = 41.0g * 0.25 J/(g°C) * (T_final - 390.0°C) The heat gained by the Zn can be calculated using the formula: Q_gained = m * C_s(Zn) * (T_final - Show more…
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