If 10 kg/min of air are compressed isothermally from $p_i = 90$ kPa, $V_i = 8$ \$\text{m}^3/ ext{min}$ to $p_f = 650$ kPa, find the work, the change of entropy and the heat for nonflow process.
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We are given that the initial volume is V=8. Since the process is isothermal, the final volume can be found using the ideal gas law: p1V1 = p2V2 where p1 = 90 kPa, V1 = 8, p2 = 650 kPa, and V2 is the final volume. Solving for V2: V2 = (p1V1) / p2 = (90 kPa Show more…
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