Question

You’re working on a reaction that involves liquid acetaldehyde (C2H4O) which reacts with liquid hydrogen cyanide (HCN) to form liquid 2-hydroxypropanenitrile (C3H5NO). You combine 5 mL of 20 M acetaldehyde with 3.5 mL of 15 M hydrogen cyanide and you yield 1.5 g of 2-hydroxypropanenitrile. There is a central carbon in both acetaldehyde and 2-hydroxypropanenitrile. What is the hybridization of the central carbon molecular orbital on the reactant side of the equation for acetaldehyde? What is the hybridization of the central carbon molecular orbital on the product side of the equation for 2-hydroxypropanenitrile?

          You’re working on a reaction that involves liquid acetaldehyde (C2H4O) which reacts with liquid hydrogen cyanide (HCN) to form liquid 2-hydroxypropanenitrile (C3H5NO). You combine 5 mL of 20 M acetaldehyde with 3.5 mL of 15 M hydrogen cyanide and you yield 1.5 g of 2-hydroxypropanenitrile.

There is a central carbon in both acetaldehyde and 2-hydroxypropanenitrile. What is the hybridization of the central carbon molecular orbital on the reactant side of the equation for acetaldehyde? What is the hybridization of the central carbon molecular orbital on the product side of the equation for 2-hydroxypropanenitrile?

Added by Escarly V.

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