7. A force of 250 N is applied to a hydraulic jack piston that is 0.02 m in diameter. If the piston that supports the load has a diameter of 0.15 m, approximately how much mass can be lifted by the jack? Ignore any difference in height between the pistons.
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The formula for the area of a circle is πr², where r is the radius of the circle. The radius is half of the diameter, so the radius of the small piston is 0.01 m and the radius of the large piston is 0.075 m. The area of the small piston is π*(0.01 m)² = 0.000314 Show more…
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