00:01
Here the given conditions are p of 1 plus p of minus 1 is equal to 0 and p of 2 plus p of minus 2 is equal to 0.
00:14
Now consider a general polynomial in p4 as p of x is equal to a into x raised to 4 plus b into x cube plus c x square plus dx plus e.
00:32
Call it equation 1.
00:35
Now find polynomial that satisfies the given conditions.
00:41
For that first evaluate these conditions for the general polynomial.
00:46
So we have p of 1 plus p of minus 1 as a plus b plus c plus d plus e plus a minus b plus c minus d plus e is equal to 2a plus 2c plus 2e and p of 2 plus p of minus 2 is equal to 16a plus 8b plus 4c plus 2d plus e plus 16a minus 8b plus 4c minus 2d plus e which is equal to 32a plus 8c plus 2e.
01:46
Now since the conditions are p of 1 plus p of minus 1 is equal to 0.
01:55
So we have 2a plus 2c plus 2e is equal to 0.
02:02
Call it equation 2 and the other condition is p of 2 plus p of minus 2 is equal to 0.
02:10
So we have 32a plus 8c plus 2e is equal to 0.
02:18
Call it equation 3.
02:19
From equation 2 we have 2a is equal to minus 2c minus 2e.
02:31
That means a is equal to minus c minus e.
02:34
Now put this value of a into equation 3...