For the reaction $p + p \rightarrow 3p + \overline{p}$, where one of the initial protons is at rest, use relativistic formulas to show that the threshold energy is $6m_pc^2$, equal to three times the magnitude of the $Q$-value of the reaction, where $m_p$ is the proton mass. [$Hint$: Assume all final particles have the same velocity.]