Unequal-mass collision. In the collision of two particles, the reference frame in which one is initially at rest and the other moving with velocity $v$ is called the laboratory frame. Suppose the moving mass is $m$ and the stationary one is $2 m$.
(a) What is the velocity of the center-of-mass frame (see Prob.
9) with respect to the laboratory frame?
(b) How much kinetic energy is lost in both the laboratory and center-of-mass frames in a completely inelastic collision, i.e., one in which the particles stick together?
(c) If the collision is elastic, the velocities of the particles in the center-of-mass frame are changed in direction but not in magnitude. Find an expression relating the angle of deviation (usually called angle of scattering) of the mass $m$ in the laboratory and in the center-of-mass frames.
Note that in the center-of-mass frame, the angle of the second particle is always $180^{\circ}$ from the angle of the first. In the equal-mass collision, $\theta_{\mathrm{lab}}=\theta_{\mathrm{c} . \mathrm{m}} / 2 .$ Vector diagrams are instructive.