00:02
Good day everyone.
00:03
So here for our solution, first one is for part a.
00:07
So we need to find what is the force of one plate.
00:11
So basically we have f, one is equals to f, divided by two.
00:16
So we have equal to e, zero, e raised to the power of two, divided by two.
00:22
And the energy density of the electric field is we have u e is equals to negative one half e o.
00:29
We have e raised to the power of two.
00:32
So this is negative because the plates are drawn towards each other.
00:36
Now for part b, we need to identify the factors that do appears because we are considering an amperian loop of length or symmetric about the sheet.
00:47
Therefore we have b is equals to u o j s divided by two, which is due to one plate...