A jet is diving vertically downward at $1200 \mathrm{km} / \mathrm{h}$. If the pilot can withstand a maximum acceleration of $5 g$ (i.e., 5 times Earth's gravitational acceleration) before losing consciousness, at what height must the plane start a $90^{\circ}$ circular turn, from vertical to horizontal, in order to pull out of the dive? See Fig. $3.25,$ assume the speed remains constant, and neglect gravity.
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