A sulphate of a metal (a) on heating evolves two gases
(b) and (c) and an oxide. Gas (b) turns $\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}$ paper green while gas (c) forms a trimer in which there is no $\mathrm{S}-\mathrm{S}$ bond. Compound (d) with $\mathrm{HCl}$, forms a Lewis base (E) which exists as a dimmer. Compounds (a),
(b), (c), (d) and (E) are respectively.
(a) $\mathrm{FeS}, \mathrm{SO}_{2}, \mathrm{SO}_{3}, \mathrm{FeSO}_{4}, \mathrm{FeCl}_{3}$
(b) $\mathrm{FeS}, \mathrm{SO}_{2}, \mathrm{SO}_{3}, \mathrm{Fe}_{2}(\mathrm{PO} 4)_{3}, \mathrm{FeCl}_{2}$
(c) $\mathrm{FeSO}_{4}, \mathrm{SO}_{2}, \mathrm{SO}_{3}, \mathrm{Fe}_{2} \mathrm{O}_{3}, \mathrm{FeCl}_{3}$
(d) $\mathrm{Al}_{2}\left(\mathrm{SO}_{4}\right)_{3}, \mathrm{SO}_{2}, \mathrm{SO}_{3}, \mathrm{Al}_{2} \mathrm{O}_{3}, \mathrm{FeCl}_{3}$