An abelian group $W$ is a Whitehead group if $\operatorname{Ext}_{\mathbb{Z}}^{1}(W, \mathbb{Z})=\{0\} \cdot^{3}$
(i) Prove that every subgroup of a Whitehead group is a Whitehead group.
(ii) Prove that $\operatorname{Ext}_{\mathbb{Z}}^{1}(A, \mathbb{Z}) \cong \operatorname{Hom}_{\mathbb{Z}}\left(A, S^{1}\right)$ if $A$ is a torsion group and $S^{1}$ is the circle group. Prove that if $A \neq\{0\}$ is torsion, then $A$ is not a Whitehead group; conclude further that every Whitehead group is torsion-free.
Hint. Use Exercise $7.17 .$
(iii) Let $A$ be a torsion-free abelian group of rank 1; i.e., $A$ is a subgroup of $\mathbb{Q}$. Prove that $A \cong \mathbb{Z}$ if and only if $\operatorname{Hom}_{\mathbb{Z}}(A, \mathbb{Z}) \neq\{0\} .$
(iv) Let $A$ be a torsion-free abelian group of rank 1. Prove that if $A$ is a Whitehead group, then $A \cong \mathbb{Z}$.
Hint. Use an exact sequence $0 \rightarrow \mathbb{Z} \rightarrow A \rightarrow T \rightarrow 0$, where $T$ is a torsion group whose $p$-primary component is either cyclic or isomorphic to Prüfer's group of type $p^{\infty}$.
(v) (K. Stein). Prove that every countable $^{4}$ Whitehead group is free abelian.
Hint. Use Exercise $3.4$ on page 114 , Pontrjagin's Lemma: if $A$ is a countable torsion-free group and every subgroup of $A$ having finite rank is free abelian, then $A$ is free abelian.