00:01
So for this problem, we have a family of circles described by the equation x squared plus y squared is equal to r squared.
00:09
And what you wanted to do is to show that all the normal lines to this circle, for this family of circles, will actually pass through the center of this circle.
00:21
And just to emphasize, this circle has the center at the origin.
00:26
Okay.
00:28
So how are we going to prove that? the first thing i wanted to do is to find out the slope of tangent and therefore the normal as well.
00:43
And i can do that by differentiating the equation of the circle.
00:46
So we'll end up having 2x tx just 2 .y t y is equal to 0 and simply d .y over tx is negative x over y.
00:57
And take note that this expression here is the slope of the tangent line.
01:02
And that being said, since the normal is perpendicular to the tangent line, the slope of the normal line is just the negative reciprocal of this one.
01:12
So that should be y over x.
01:16
Okay.
01:19
Now, if i will create an equation, equation of normal line that is passing perpendicular to a tangent at x .1 comma y sub 1 will end up having this equation.
01:48
Minus y of 1 is equal to the slope of the normal line times x minus x of 1...