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Cornell University

Numerade Educator

University of Washington

Simon Fraser University

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welcome to our third example video. Looking at the double slit interference and diffraction grating setups in this video, we're going to consider a diffraction grating set up where we have a gap with many slits per millimeter here. And we're going to say that on the wall behind it, we see the M equals one slit at a data equal to 25 degrees. Given this, we'd like to know what will the data be for the M equals to slit. Okay, um, given this remembering our equations for the diffraction grating we have de sign data is equal to M times Lambda. So if we have m equals one is a particular angle, what can we find out? Well, uh, we know em would be one, and we'd be able to find the ratio of D over lambda, which is going to be constant. So since we know the ratio of D over Lambda when we go to find what data to will be, so that's a sign of data to will be equal to M Times Lambda over D. In this case, M will be too, and Lambda over D is a constant. So that's going to be sign of theta one divided by one. We've inverted it here, and that will be equal to our science data to so angle Theta two will be the inverse sign of two times sign of data one, which is 25 degrees. So, um, we're able to find from this not necessarily D or Lambda, but if we confined their ratio to be a constant, then we can plug that in and predict where the other fringes ought to be.

University of North Carolina at Chapel Hill

Reflection and Refraction of Light

Relativity

Quantum Physics

Atomic Physics

Nuclear Physics