A converging lens with focal length $3.00 \mathrm{cm}$ is placed $4.00 \mathrm{cm}$ to the right of an object. A diverging lens with focal length $-5.00 \mathrm{cm}$ is placed $17.0 \mathrm{cm}$ to the right of the converging lens. (a) At what location(s), if any, can you place a screen in order to display an image? (b) Repeat part (a) for the case where the lenses are separated by $10.0 \mathrm{cm}.$