Nick Weber

Grand Valley State University
Teacher

Biography

I am a high school biology and chemistry teacher. I love all things science and nature and spend as much time as I can outdoors hiking, backpacking, hammocking, snorkeling, scuba diving. I also am an avid volleyball player and am an assistant varsity girls volleyball coach.

Education

BS Biology
Grand Valley State University

Educator Statistics

Numerade tutor for 4 years
102 Students Helped

Topics Covered

Mendelian Genetics: Understanding Inheritance Patterns
The Central Dogma: Understanding Gene Expression

Nick's Textbook Answer Videos

1

Nick's Quick Ask Videos

06:49
Biology

Mutation Practice
DNA template:
3’
CGG ATA TAC CGC TTA GCG TGG AGC ATC GGG GGG GCG CCC
5’
5’
GCC TAT ATG GCG AAT CGC AGG TCG TAG CCC CCC CGC GGG
3’
Mutated DNA template:
3’
CGG ATA TAC CGG TTA GCG TGG AGC ATC GGG GGG GCG CCC
5’
5’
GCC TAT ATG GCG AAT CGC AGG TCG TAG CCC CCC CGC GGG
3’
1. Using the mutated DNA template create the
mRNA.
2. Create your amino acid sequence from the mRNA
created in question 1.
3. Highlight on the DNA where the mutation
happened.
4. What type of mutation has occurred? To
help with this question use the amino acid sequence produced in the
protein synthesis in the previous practice problem for
comparision.
5. Will this mutation still create a functional
protein? Why or why not?

Nick Weber
01:33
Biology

For this question, it may serve you best to make a Punnett square with these guidelines: you have 2 Guinea pigs who mated. These animals are bright green! Both mom and dad are heterozygous green. We'll call that Gg. So for both parents, the genotype is Gg and the phenotype is green. The color coats possible are green and yellow. Yellow is the recessive trait. Knowing this, if you make a square with 4 baby Guinea pigs, how many out of 4 will be green?
Select one: a. 1 b. 2 c. 3 d. 4

Nick Weber
03:27
Biology

A eukaryotic diploid cell from an organism with the XX-XY sex determination system has two pairs of autosomes and a pair of sex chromosomes, X and Y.

1. A diploid cell from this individual undergoes meiosis. Which of the following is a possible normal combination of chromosomes in one of the gamete cells after the completion of meiosis II (assuming meiosis occurred correctly)?
a) A chromosome with the 'A' allele, one with the 'a' allele, one with the 'B' allele, one with the 'b' allele, and one X.
b) A pair of chromosomes with 'A' alleles, a pair of chromosomes with 'B' alleles, and a pair of Y chromosomes.
c) One chromosome with an 'a' allele, one chromosome with a 'B' allele, and one X.
d) One chromosome with the 'A' allele, one with the 'B' allele, one X, and one Y.

Nick Weber
01:56
Biology

Morgan breeds and sells snakes. He knows that he can make the
most money by breeding and selling albino snakes. Albinism is a
recessive trait. His female albino corn snake just produced six
offspring. Two displayed normal coloration and four were albino.
What do you know about the genotype of the baby snakes with the
normal coloration?
A) They must be heterozygous.
B) They must be homozygous dominant.
C) They could be either heterozygous or homozygous dominant.
D) They must be homozygous recessive.
E) There is not enough information to determine their genotype
but we know that they must carry the dominant allele.

Nick Weber
03:06
Biology

Which is more dense, Silver AG or Carbon C, and why? How many
valence electrons do they each have and why?

Nick Weber
03:52
Biology

In exotic guinea pigs, pink coat color is specified by a dominant allele of the B gene. Individuals that are homozygous recessive (bb) have blue coats. A dominant allele of the E gene allows for the expression of the B gene. Individuals that are homozygous recessive (ee) do not express the B gene and have yellow coats. Two individuals heterozygous for both genes have a litter of colorful baby guinea pigs. What percentage of the offspring will have blue coats?

Nick Weber
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