7. There is a radius of orbit around the Earth such that the period of the orbit is 24 hours. A satellite in orbit at this radius, above the Earth's equator and moving in the same direction as the Earth's rotation, will appear to be "stationary" relative to the Earth's surface. We are going to solve for the radius of the orbit that has a period of 24 hours. We can begin with the equation Fcent = Fgrav, where r is the unknown radius we are solving for. We can make the substitution v^2 = arlT. The mass ms cancels, leaving an equation with the only variables being r and the period T. Since we are going to set the period to be 24 hours, we can solve for the radius r. a) At what radius is the period of orbit equal to 24 hours? b) This radius is equal to how many times the Earth's radius? ans. b) 6.62