00:01
Hi friends, as we know that magnetic field at a point due to moving charge is given by mu not q cross product of velocity vector and position vector divided by 4 pi r square and its magnitude can be written as mu not qb 4 pi r sign of theta total fate produced by the 2 charges is vector sum of field produced by individual charge.
01:05
So it can be written as field due to the electron and field due to proton.
01:15
Now substitute the value mu not upon 4 pi e v.
01:25
R .e squared minus j unit vector, mu not upon 4 pi.
01:44
Just a moment.
01:51
R p square z unit vector so it could be written as mu not upon four pi you can take common eve upon r e square r p square now substitute the value 1 .6 into 10 to the power minus 19 will be common 845 into 5 by 18 1 upon 5 .5 into 10 to the power the power minus 9 plus 4 into 10 to the power minus 9 square.
02:50
So on solving it, magnetic field you will get 1 .39 into 10 to the power minus 3 tesla into the paper.
03:02
This is the answer of part a.
03:06
Now part b, magnetic field produced by electron at the position of proton, at the position of proton.
03:43
R will be 5mm square plus 4mm square...