$15 \mathrm{~mL}$ of gaseous hydrocarbon requires $45 \mathrm{~mL}$ of oxygen for complete combustion which produces $30 \mathrm{~mL}$ of $\mathrm{CO}_{2}$ gas, measured under identical conditions. The formula of the hydrocarbon is $\mathrm{C}_{x} \mathrm{H}_{y}$. The ratio $\underline{\mathrm{y}}$ is X