Question
$2.1 \mathrm{~g}$ of Fe combines with S cvolving $3.77 \mathrm{~kJ}$. The heat of formation of FeS in $\mathrm{kJ} / \mathrm{mol}$ is(1) $3.77$(2) $1.78$(3) $100.5$(4) Nonc
Step 1
The molar mass of Fe is approximately 55.85 g/mol. So, the number of moles of Fe is given by: \[n = \frac{m}{M} = \frac{2.1 \, \text{g}}{55.85 \, \text{g/mol}} = 0.0376 \, \text{mol}\] Show more…
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