Given the bond energies of $\mathrm{N} \equiv \mathrm{N}, \mathrm{H}-\mathrm{H}$ and $\mathrm{N}-\mathrm{H}$
bonds as 945,436 and $391 \mathrm{~kJ}$ mol $^{1}$, respectively, the enthalpy of the reaction $\mathrm{N}_{2}(\mathrm{~g})+3 \mathrm{H}_{2}(\mathrm{~g}) \rightarrow 2 \mathrm{NH}_{3}(\mathrm{~g})$ is
(1) $-93 \mathrm{~kJ}$
(2) $102 \mathrm{~kJ}$
(3) $90 \mathrm{~kJ}$
(4) $105 \mathrm{~kJ}$