Given NII3( g)+3 Cl2( g) ⇌NCl3( g)+3 IICl (g) ; II1 N2( g)+3 H2( g) ⇌2 NH3( g) ; H2 II2( g)+Cl2(

Name: Problem 63, Chapter 6: Objective Chemistry for Engineering and Medical Entrance Examinations
Uploaded: 2022-01-25T18:39:24-08:00
Duration: 1 min 24 s
Channel: Mishal Gul
Description: Given NII3( g)+3 Cl2( g) ⇌NCl3( g)+3 IICl (g) ; II1 N2( g)+3 H2( g) ⇌2 NH3( g) ; H2 II2( g)+Cl2( g) ⇌2 IICl ; II3 The heat of formation of NCl3(g) in the terms of Δl l1 Δl I2 and Δ/ I3 is (1) ΔHf=ΔH1+(Δ/ I2)/(2)-(3)/(2) ΔH3 (2) Δ/ If=Δ/ I1+(ΔH2)/(2)-(3)/(2) Δl l3 (3) ΔHf=ΔH1+(Δl I2)/(2)-(3)/(2) ΔH3 (4) None

step 1 Given the following reversible reactions, there are three types of reactions given and ultimatel

Question

Given $\mathrm{NII}_{3}(\mathrm{~g})+3 \mathrm{Cl}_{2}(\mathrm{~g}) \rightleftharpoons \mathrm{NCl}_{3}(\mathrm{~g})+3$ IICl $(\mathrm{g}) ; \mathrm{II}_{1}$ $\mathrm{N}_{2}(\mathrm{~g})+3 \mathrm{H}_{2}(\mathrm{~g}) \rightleftharpoons 2 \mathrm{NH}_{3}(\mathrm{~g}) ; \mathrm{H}_{2}$ $\mathrm{II}_{2}(\mathrm{~g})+\mathrm{Cl}_{2}(\mathrm{~g}) \rightleftharpoons 2 \mathrm{IICl} ; \mathrm{II}_{3}$ The heat of formation of $\mathrm{NCl}_{3}(g)$ in the terms of $\Delta l l_{1}$ $\Delta l I_{2}$ and $\Delta / I_{3}$ is (1) $\Delta H_{f}=\Delta H_{1}+\frac{\Delta / I_{2}}{2}-\frac{3}{2} \Delta H_{3}$ (2) $\Delta / I_{\mathrm{f}}=\Delta / I_{1}+\frac{\Delta H_{2}}{2}-\frac{3}{2} \Delta l l_{3}$ (3) $\Delta H_{f}=\Delta H_{1}+\frac{\Delta l I_{2}}{2}-\frac{3}{2} \Delta H_{3}$ (4) None

   Given $\mathrm{NII}_{3}(\mathrm{~g})+3 \mathrm{Cl}_{2}(\mathrm{~g}) \rightleftharpoons \mathrm{NCl}_{3}(\mathrm{~g})+3$ IICl $(\mathrm{g}) ; \mathrm{II}_{1}$
$\mathrm{N}_{2}(\mathrm{~g})+3 \mathrm{H}_{2}(\mathrm{~g}) \rightleftharpoons 2 \mathrm{NH}_{3}(\mathrm{~g}) ; \mathrm{H}_{2}$
$\mathrm{II}_{2}(\mathrm{~g})+\mathrm{Cl}_{2}(\mathrm{~g}) \rightleftharpoons 2 \mathrm{IICl} ; \mathrm{II}_{3}$
The heat of formation of $\mathrm{NCl}_{3}(g)$ in the terms of $\Delta l l_{1}$ $\Delta l I_{2}$ and $\Delta / I_{3}$ is
(1) $\Delta H_{f}=\Delta H_{1}+\frac{\Delta / I_{2}}{2}-\frac{3}{2} \Delta H_{3}$
(2) $\Delta / I_{\mathrm{f}}=\Delta / I_{1}+\frac{\Delta H_{2}}{2}-\frac{3}{2} \Delta l l_{3}$
(3) $\Delta H_{f}=\Delta H_{1}+\frac{\Delta l I_{2}}{2}-\frac{3}{2} \Delta H_{3}$
(4) None

Objective Chemistry for Engineering and Medical Entrance Examinations

K Rama Rao 1st Edition

Chapter 6, Problem 63

Instant Answer

Solved by Expert Mishal Gul

01/25/2022

Step 1

Step 1: We are given the following reactions: (i) $\mathrm{NII}_{3}(\mathrm{~g})+3 \mathrm{Cl}_{2}(\mathrm{~g}) \rightleftharpoons \mathrm{NCl}_{3}(\mathrm{~g})+3$ IICl $(\mathrm{g}) ; \mathrm{II}_{1}$ (ii) $\mathrm{N}_{2}(\mathrm{~g})+3 Show more…

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Given $\mathrm{NII}_{3}(\mathrm{~g})+3 \mathrm{Cl}_{2}(\mathrm{~g}) \rightleftharpoons \mathrm{NCl}_{3}(\mathrm{~g})+3$ IICl $(\mathrm{g}) ; \mathrm{II}_{1}$ $\mathrm{N}_{2}(\mathrm{~g})+3 \mathrm{H}_{2}(\mathrm{~g}) \rightleftharpoons 2 \mathrm{NH}_{3}(\mathrm{~g}) ; \mathrm{H}_{2}$ $\mathrm{II}_{2}(\mathrm{~g})+\mathrm{Cl}_{2}(\mathrm{~g}) \rightleftharpoons 2 \mathrm{IICl} ; \mathrm{II}_{3}$ The heat of formation of $\mathrm{NCl}_{3}(g)$ in the terms of $\Delta l l_{1}$ $\Delta l I_{2}$ and $\Delta / I_{3}$ is (1) $\Delta H_{f}=\Delta H_{1}+\frac{\Delta / I_{2}}{2}-\frac{3}{2} \Delta H_{3}$ (2) $\Delta / I_{\mathrm{f}}=\Delta / I_{1}+\frac{\Delta H_{2}}{2}-\frac{3}{2} \Delta l l_{3}$ (3) $\Delta H_{f}=\Delta H_{1}+\frac{\Delta l I_{2}}{2}-\frac{3}{2} \Delta H_{3}$ (4) None

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Key Concepts

Enthalpy of Formation

The enthalpy of formation is defined as the heat change that results when one mole of a compound is formed from its constituent elements in their standard states. It is a fundamental concept in thermochemistry used to understand reaction energetics.

Hess's Law

Hess's Law states that the total enthalpy change for a reaction is the same regardless of the pathway taken, allowing the summing of individual reaction enthalpies to equal the overall reaction enthalpy. This principle is crucial when combining multiple reactions to determine the enthalpy change for a target reaction.

Reaction Enthalpy Manipulation

Reaction enthalpy manipulation involves algebraically adding, subtracting, and scaling known reaction enthalpies to derive the enthalpy change for a desired reaction. This technique relies on the conservation of energy and is a direct application of Hess's Law in calculating formation enthalpies from given reaction steps.

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