Given that $Q = 3.30 \times 10^{-9} \, \text{C}$ and $V = 220 \, \text{V}$, we can substitute these values into the formula to find the capacitance:
\[C = \frac{3.30 \times 10^{-9} \, \text{C}}{220 \, \text{V}} = 15 \times 10^{-12} \, \text{F} = 15 \, \text{pF}\]
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