00:01
In the given problem, there is a parallel plate air capacitor whose capacitance has been given as 920 picofarret.
00:14
The charge over the plates of the capacitor is given as 2 .55 microcoulawn.
00:22
Now in the first part of the problem, we have to find the potential difference across the plates of the capacitor.
00:30
That is given as the ratio of q and c means v equals to q by c.
00:35
So this is 2 .55 into 10 dash per minus 6 coulomb.
00:43
We can say it and for capacitance this is 920 for pico this is 10 to minus 12 ferret.
00:51
So finally this answer for the voltage comes out to be 2 .7 into 10 dash to the part 3 volt.
01:07
So this is the answer for the first part of the problem the potential across the plates of the capacitor is 2 .77 into 10 to the power 3 volt answer for the first part.
01:19
Now in the second part of the problem they are saying the distance between the plates of the capacitor is doubled.
01:29
So using the expression for capacitance c is equal to epsilon note a by d it is clear that capacitance depend capacitance of the capacitor depends inversely on the pellet separation so on doubling this plate separation on doubling the plate separation d the capacitance will be will become half the capacitance c will become half means to say c -d is equal to c by 2 as the capacitance becomes half...