3 -phenylpropene on reaction with HBr gives (as a major product) (a) C6 H5 CH2 CH(Br) CH3 (b) C6

step 1 In this problem I can write D -DX and H C6 H5 CH double bond CH CH 3 plus HBR it will give it wi

3 -phenylpropene on reaction with HBr gives (as a major...

3 -phenylpropene on reaction with HBr gives (as a major product) (a) $\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CH}_{2} \mathrm{CH}(\mathrm{Br}) \mathrm{CH}_{3}$ (b) $\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CH}(\mathrm{Br}) \mathrm{CH}_{2} \mathrm{CH}_{3}$ (c) $\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{Br}$ (d) $\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CH}(\mathrm{Br}) \mathrm{CH}=\mathrm{CH}_{2}$

3 -phenylpropene on reaction with HBr gives (as a major product)
(a) $\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CH}_{2} \mathrm{CH}(\mathrm{Br}) \mathrm{CH}_{3}$
(b) $\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CH}(\mathrm{Br}) \mathrm{CH}_{2} \mathrm{CH}_{3}$
(c) $\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{Br}$
(d) $\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CH}(\mathrm{Br}) \mathrm{CH}=\mathrm{CH}_{2}$

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Key Concepts

Electrophilic Addition Mechanism

This mechanism involves the addition of an acid (HBr) to an alkene where the ? bond electrons attack a proton (H+), forming a carbocation intermediate. Following this, the bromide ion attacks the carbocation. This stepwise sequence is key to predicting the outcome of the reaction.

Markovnikov's Rule

Markovnikov's rule dictates that in the addition of HX to an unsymmetrical alkene, the hydrogen attaches to the carbon with the greater number of hydrogen atoms, leading to the formation of the more stable carbocation. This rule is essential for determining the regiochemistry of the addition.

Carbocation Stability

The formation and stability of a carbocation intermediate greatly influence the reaction pathway. In this context, a benzylic carbocation, where the positive charge is adjacent to a benzene ring, is particularly stabilized by resonance compared to non-benzylic carbocations, thus directing the formation of the major product.

Resonance Stabilization

Resonance stabilization involves the delocalization of the positive charge over a larger structure, such as an aromatic ring. In reactions where a benzylic carbocation is formed, this delocalization lowers the energy of the intermediate, making it more stable and consequently favoring its formation in the product distribution.

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