The major product formed in the reaction of HBr with (CH3)2 CH-CH=CH2 is (a) (b) (CH3)2 CH-CH2-C

step 1 In this problem I can write the reaction as CH3 CH3 CH3 , double one CH2 in presence of H plus w

The major product formed in the reaction of HBr with (CH3)2...

The major product formed in the reaction of $\mathrm{HBr}$ with $\left(\mathrm{CH}_{3}\right)_{2} \mathrm{CH}-\mathrm{CH}=\mathrm{CH}_{2}$ is (a) (b) $\left(\mathrm{CH}_{3}\right)_{2} \mathrm{CH}-\mathrm{CH}_{2}-\mathrm{CH}_{2} \mathrm{Br}$ (c) $\left(\mathrm{CH}_{3}\right)_{2} \mathrm{CH}-\mathrm{CHBr}-\mathrm{CH}_{3}$ (d)

The major product formed in the reaction of $\mathrm{HBr}$ with $\left(\mathrm{CH}_{3}\right)_{2} \mathrm{CH}-\mathrm{CH}=\mathrm{CH}_{2}$ is
(a)
(b) $\left(\mathrm{CH}_{3}\right)_{2} \mathrm{CH}-\mathrm{CH}_{2}-\mathrm{CH}_{2} \mathrm{Br}$
(c) $\left(\mathrm{CH}_{3}\right)_{2} \mathrm{CH}-\mathrm{CHBr}-\mathrm{CH}_{3}$
(d)

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Key Concepts

Electrophilic Addition Reaction

This reaction involves the addition of an electrophile and a nucleophile to a multiple bond, typically an alkene. The double bond acts as a nucleophile and attacks an electrophilic species, leading to the formation of a carbocation intermediate which is later attacked by a nucleophile to form the final addition product.

Markovnikov's Rule

This rule predicts the outcome of electrophilic additions to unsymmetrical alkenes, stating that the hydrogen atom in the adding molecule (such as HBr) will attach to the carbon with more hydrogen atoms, while the halide attaches to the carbon with fewer hydrogen atoms. This guideline helps in determining the regiochemistry of the product formed.

Carbocation Stability

The stability of the carbocation intermediate formed during the reaction plays a crucial role in determining the product. More substituted carbocations (those with greater alkyl substitution) are more stable due to hyperconjugation and inductive effects, leading the reaction to favor pathways that produce these intermediates over less substituted alternatives.

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