Question
$49-54$ Use the Comparison Theorem to determine whether the integral is convergent or divergent.$$\int_{0}^{1} \frac{\sec ^{2} x}{x \sqrt{x}} d x$$
Step 1
So, we define our function $f(x)$ as follows: $$f(x) = \frac{\sec^2 x}{x \sqrt{x}} = \frac{\sec^2 x}{x^{3/2}}$$ Show more…
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