00:01
Okay, so today we're going to be going over question number five.
00:05
And let's have cl cl cl here.
00:18
Double one to two and o single one to two and oh plus och3.
00:30
You have your pairs of electrons.
00:34
And there is a minus charge.
00:36
So in this case, too, in order to identify which one of these is the acid and which one is the base, you have to look to see which one has the capability of donating a proton, and that will be your acid, and which one has the capability of accepting a proton, and that one will be your base.
00:59
So in this case, when you look at both of the two species, the one that can donate is going to, going to be your first one because you have your oh group.
01:14
So this is going to be your acid, which means this is going to be your base.
01:22
So your products since this species gave up its proton, it except this one will accept it.
01:38
So it's going to be ch3oh plus.
01:48
So you have, let's see, c l, carbon, cl, cl, carbon, double pointed to an o.
02:08
And then since it lost the hydrogen, you're going to have a hydrogen here.
02:14
But it's going to have a minus charge.
02:22
B, you have cl, cl.
02:27
Cl cl, cl.
02:33
And this one is triple bonded to an h plus h with its two electrons and a minus charge.
02:44
So on this case, the one that can't donate is going to be your first one.
02:49
So that is going to be your acid.
02:51
The second one is going to be your piece...