00:01
Giving i to be equal to this integral, so this is a proper integral.
00:06
And we are saying that if both this and this are convergent, then we can write this integral in the form of dates.
00:16
So this then is equal to that and this can also be rewrites or rewritten in this form.
00:25
So then this implies that our integral from negative, infinity to infinity of x e to the power minus x squared the x will be equal to the integral from negative infinity to e you have x e to the power minus x squared the x plus the integral from a to infinity x e to the power minus x squared d x so this then it's equal to the limits.
01:06
So for this part as t approaches negative infinity, you have the integral from t to 0 of x, e to the power minus x squared the x, then plus this integral will be equal to the limits as t approaches infinity.
01:28
You have the integral from zero to t of x, e to the power negative x squared d x so this will be equal to this then it's equal to negative 1 divided by 2 the limits as t approaches negative infinity we have e to the power minus x squared from t to 0 plus so negative here...