00:01
A 0 .25 mole sample of a weak acid with an unknown pcaa was combined with 10 milliliters of 3 molar potassium hydroxide.
00:08
And the resulting solution was diluted to 1 .5 liters.
00:11
The measured ph of the solution was 3 .85.
00:14
What is the pca of the weak acid? so the first thing we want to do is find out how many moles of the base were added into our weak acid.
00:23
So let's convert milliliters to liters and then multiply by the molarity.
00:28
That will give us 0 .0300 moles of the k -oh, which is equal to the moles of the hydroxide because it's a strong base, so it completely dissociates.
00:40
I'm going to use ha to represent the unknown acid, and when it reacts with that hydroxide that we added in, it's going to form our conjugate base and some water.
00:57
So if we form an ice chart, we had 0 .25 moles of the ha to begin with, and we added in 0 .03 moles of the base, and we don't have any of our conjugate acid...