The formula for heat is $Q = mc\Delta T$, where $m$ is the mass, $c$ is the specific heat, and $\Delta T$ is the change in temperature. In this case, $m = 100$ g, $c = 0.03$ cal/g°C, and $\Delta T = 20$°C - $0$°C = $20$°C. So, the total heat in the bullet is:
\[Q
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