00:01
In this question we have two resistors in series.
00:03
Okay, one is 1 .5 mega oms and the other one is 2 .5 mega oms.
00:12
Okay, it's connected to a battery and then we are given that, this is 6 volts.
00:21
So we want to find the emf of the battery and the current in the circuit.
00:25
Okay, so to do part a, okay, let's call this r1, r2, okay, r1 is 1 .5 mega -oom, r2 is 2 .5 mega -oom.
00:42
So we know that the current is the same in a series circuit, which means that current is the same in series circuit, which means that i -1 equals to i -2, v -1 over r1 equals to v -2 over r2.
01:11
So to find the emf of the battery, we need to find v2 first.
01:18
So v2 is equal to r2 over r1 times v1.
01:24
And this is 2 .5 divided by 1 .5 times 6...