Question
A 1500 -kg car is moving at $20.0 \mathrm{m} / \mathrm{s}$. The driver brakes toa stop. The brakes cool off to the temperature of the surrounding air, which is nearly constant at $20.0^{\circ} \mathrm{C}$. What is the total entropy change?
Step 1
The kinetic energy (K.E.) of an object can be calculated using the formula: \[ K.E. = \frac{1}{2} m v^2 \] where \( m \) is the mass of the object and \( v \) is its velocity. Show more…
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A 1 500-kg car is moving at 20.0 m/s. The driver brakes to a stop. The brakes cool off to the temperature of the surrounding air, which is nearly constant at $20.0^{\circ} \mathrm{C}$ . What is the total entropy change?
$A 1500-k g$ car is moving at 20.0 $\mathrm{m} / \mathrm{s}$ . The driver brakes to a stop. The brakes cool to the temperature of the surrounding air, which is nearly constant at $20.0^{\circ} \mathrm{C} .$ What is the total entropy change? You may use the result of Problem $31 .$
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