00:01
And this problem, the key is knowing how to draw a free body diagram so we can see the forces acting on the object.
00:08
So if you think of a person sitting on a chair, they'll have a force due to gravity pointing straight down, and that's its weight.
00:15
So you have mass times gravity.
00:18
And acting in the exact opposite direction, you have the normal force.
00:22
And if the person on the chair is being pushed to the right, we'll have a force to the right.
00:28
And if it experiences friction, friction will be in the opposite direction of the motion.
00:35
This would be kinetic friction because there's movement.
00:40
So once you can draw that and see the forces, you can easily solve for either variable to get a number.
00:47
So in here we have a book that weighs 25 kilograms that's on a loading ramp.
00:56
And it experiences two types of friction.
00:58
First, kinetic friction.
00:59
So we're given the coefficient of kinetic friction.
01:04
This is friction due to movement, which is 0 .25.
01:07
And also static friction.
01:09
This is friction when it's just sitting there.
01:12
And we're given the coefficient of static friction, which is 0 .35.
01:19
And so for part a, we want to find the angle theta that will cause the book to slide down the ramp.
01:30
So it'll look like something like this, or the book.
01:34
Will begin to move down the ramp.
01:39
So let's first draw a free body diagram this book.
01:43
So again, we have the weight straight down.
01:47
And because it's at an angle, it'll have components.
01:50
So we have w .y in the y direction.
01:55
And then down the ramp will be weight in the x direction.
02:02
And the exact opposite of w .y will have the normal force.
02:09
And since it's about to slide down the ramp, it'll experience static friction in the opposite direction.
02:22
Static friction, the equation is coefficient of static friction times the normal force.
02:32
And for the weight, since it has components, we can say wx is w -sign theta, and w -y is w -cosined theta.
02:49
So first let's look at the forces in the x -rex.
02:53
Direction.
02:55
So looking back at a free body diagram, in the direction we have wx and we have static friction.
03:02
And if we say down the ramp and straight down is positive, that in the x direction we have wx, which is w sine theta minus static friction, which is mu s times the normal force, equals since it's about to move the acceleration is zero.
03:26
So we have for meta.
03:28
Maybe we have zero...