00:01
A ball with the mass of 30 grams and a charge of 5 microcouons is thrown out of a window with the height of 20 meters and also with the velocity of 20 meters per second.
00:13
And there's also a magnetic field of 0 .01 tesla's that is perpendicular to the trajectory of the ball.
00:25
So we're going to start solving part a where it asks us to find what the force on the ball is due to the magnetic field.
00:33
Right before it hits the ground.
00:39
So we're going to start by saying that the velocity in the y direction is equal to the square root of 2 times g times h.
00:54
And we can calculate this velocity by plugging in g, which is 9 .8 meters per second squared, and then plugging in h, which is given as 20 meters.
01:13
And so this will give us a velocity that's equal to 19 .8 meters per second.
01:23
And now we can find the magnitude of this velocity, which i'll call v.
01:32
I'll call it v of r.
01:35
And this is going to be equal to the square root of the velocity in the x direction squared plus velocity in the y direction squared.
01:50
So this v of r, you can find by plugging in v of x direction, which is given to us by the problem as 20 meters per second.
02:07
And then we can also plug in v of y, which we just calculated.
02:16
And so this will give us a magnitude that is equal to 28 .1 meters per second.
02:28
And now the force, due to the magnetic field, we can find sq times v...